Solution | Nss Physics At Work Book 2
( m_{\text{melt}} = \frac{Q_{\text{cool}}}{L_f} = \frac{6.3 \times 10^4}{3.34 \times 10^5} \approx 0.189 , \text{kg} )
( m_{\text{melt}} = \frac{Q_{\text{cool}}}{L_f} = \frac{6.3 \times 10^4}{3.34 \times 10^5} \approx 0.189 , \text{kg} )