Isolated retrofit, stipulated assumption for unmeasured factors. Option B: All parameters measured. Card 8 – Front True or False: Power factor correction capacitors reduce kW demand charges. Card 8 – Back A: False. Capacitors reduce kvar , thus lowering kVA (apparent power), which may reduce kVA demand charges , but not kW demand. kW is real power, unchanged by capacitors.
Exception: Reduced I²R losses in cables can slightly lower kW — usually negligible. Define: Degree-Day method for estimating heating energy. Card 9 – Back A: Heating Energy (MMBtu) = (HDD × UA × 24 hr/day) / (System Efficiency × 10^6)
Savings = $2,000,000 × 0.08 = $160,000 ROI = ($160,000 / $250,000) × 100 = Card 8 – Back A: False
Note: For CEM exam, know how to compare NPV of two mutually exclusive projects. What is the primary purpose of a Measurement & Verification (M&V) Plan (IPMVP Option A or B)? Card 7 – Back A: To quantify actual energy savings from an ECM (Energy Conservation Measure) by comparing measured post-retrofit energy use to a baseline adjusted for relevant variables (weather, occupancy, production).
Subtitle: CEM Test Practice Questions & Review for the Certified Energy Manager Exam Exception: Reduced I²R losses in cables can slightly
Each card features a question, key term, formula, or scenario on the front, and a detailed, exam-relevant answer on the back. Use these cards in 15-minute bursts to reinforce your weak areas and test your recall under exam conditions. Card 1 – Front Q: What is the formula for Simple Payback Period (SPP), and what is its primary limitation in energy project evaluation? Card 1 – Back A: SPP = Initial Investment / Annual Savings
Also relevant for CEM: ASHRAE/IESNA 100 (Existing Buildings), ASHRAE 62.1 (Ventilation). Practice Question: A plant has annual energy cost $2,000,000. A project saves 8% with a $250,000 cost. What is the ROI first year? Card 13 – Back A: ROI = (Annual Savings / Project Cost) × 100 ASHRAE 62.1 (Ventilation).
= (200 × 0.75 × 0.746) / 0.90 = (111.9) / 0.90 =