Adeko 9 — Crack 56

t(i) = ROL8( c_i XOR 0x5A, 3 ) ROL8 rotates an 8‑bit value left by 3 bits.

Find an input string s (9 bytes) such that CRC32( b_0 … b_8 ) == 0x56C9A4F2 . 4.2. CRC‑32 is linear over GF(2) CRC‑32 with a fixed polynomial is a linear operation: Adeko 9 Crack 56

TABLE = crc32_table()

| Tool | Purpose | |------|---------| | | Verify that the binary is not packed. | | x64dbg (or OllyDbg ) | Dynamic debugging, breakpoints, watch registers. | | Ghidra 10.2 | Static disassembly & de‑compilation. | | Strings | Quick view of embedded literals. | | Python 3.10 | Write a small key‑generator script (optional). | | procmon / Process Explorer | Observe any hidden anti‑debug syscalls. | Tip: Run the binary once under a debugger to confirm the presence of anti‑debug checks (e.g., IsDebuggerPresent , CheckRemoteDebuggerPresent ). If they crash the program, we’ll patch them out later. 3. Static Analysis 3.1. Basic PE info File Type: PE32+ (64‑bit) Entry point: 0x140001010 Sections: .text 0x2000 (code) .rdata 0x1000 (read‑only data) .data 0x0800 (mutable data) .rsrc 0x0400 (resources – contains UI strings) The .rdata section contains the two strings we’ll see in the UI: t(i) = ROL8( c_i XOR 0x5A, 3 )

# ------------------------------------------------------------ # 2. Reverse the custom transform def invert_transform(b): """Given transformed byte b = ROL8(c ^ 0x5A, 3), recover original c.""" # Inverse of ROL8 by 3 is ROR8 by 3 r = ((b >> 3) | (b << 5)) & 0xFF c = r ^ 0x5A return c CRC‑32 is linear over GF(2) CRC‑32 with a

# ------------------------------------------------------------ if __name__ == "__main__": TARGET = 0x56C9A4F2