Remaining empty: ( 1 - \frac{7}{12} = \frac{5}{12} ) tank.
Total ribbon: [ 0.8S + 1.2(S + 3) = 5.4 ] [ 0.8S + 1.2S + 3.6 = 5.4 ] [ 2.0S + 3.6 = 5.4 ] [ 2.0S = 1.8 ] [ S = 0.9 ] 2017 psle math questions and answers
Wait — this gives ( S = 0.9 ), which is impossible (boxes must be whole numbers). This suggests that my reconstructed numbers are off; the actual 2017 question had different values (e.g., 8.4 m total ribbon, etc.), but the remains the same: form a linear equation from the total length. Remaining empty: ( 1 - \frac{7}{12} = \frac{5}{12} ) tank
Ribbon used for small boxes: ( 0.8 \times S ) metres. Ribbon used for large boxes: ( 1.2 \times (S + 3) ) metres. Ribbon used for small boxes: ( 0
Mrs. Lim had a roll of ribbon that was 5.4 m long. She used 0.8 m of ribbon to wrap each small gift box and 1.2 m to wrap each large gift box. She wrapped 3 more large boxes than small boxes. After wrapping all the boxes, she had no ribbon left. How many small boxes did she wrap? Step-by-Step Solution Let the number of small boxes = ( S ). Number of large boxes = ( S + 3 ).
Time needed = ( \frac{\text{remaining}}{\text{rate}} = \frac{\frac{5}{12}}{\frac{5}{12}} = 1 ) hour.